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Find the range of a, where z = w. Details below.
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\[z = \sum_{n=a}^{a+1}n\] \[w=\sum_{m=z}^{z+1}m\] Function w uses z, which itself uses a, where a = any real number
Big hint. \[ z=a+a+1\\ w=z+z+1 \]
You equate them then.
z = a+a+1 w=(a+a+1)+(a+a+1)+1
2a+1 = (2a+1)+(2a+1) 2a+1 = 4a+2 ------------ 2a = 4a+1| a = (4a+1)/2
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4a-2a=?
Oops, forgot the +1
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