Ask your own question, for FREE!
Chemistry 19 Online
OpenStudy (anonymous):

Explain why the quantum number set (1, 1, 0, +½) is not possible for an electron in a ground-state atom.

OpenStudy (jfraser):

each quantum number has its own allowable range, based on the other quantum numbers in the set. Do you know what each of the values stand for?

OpenStudy (anonymous):

No @JFraser can you explain this to me

OpenStudy (jfraser):

what does the first quantum number, n, stand for?

OpenStudy (jfraser):

this is the sort of thing you could quickly look up

OpenStudy (anonymous):

does it stand for number?.. @JFraser i have no idea

OpenStudy (jfraser):

'n' is the principal quantum number, it describes the overall level of the electrons

OpenStudy (jfraser):

it has values of 1, 2, 3, etc etc, always in whole numbers

OpenStudy (jfraser):

if an electron has a 'n' value of 1, that electron is in the first energy level. n = 2 the electron is in the second level (farther out than the first) n = 3 the electron is in the third level and so on

OpenStudy (jfraser):

in a set of quantum numbers, the first number is always 'n'

OpenStudy (anonymous):

oh okay, so its the energy level basically alright I understand so far! @JFraser

OpenStudy (jfraser):

the \(second\) quantum number, 'L', is the azimuth quantum number

OpenStudy (jfraser):

it describes the \(shape\) of the orbital

OpenStudy (jfraser):

the values of L are limited by the allowable value of n for that particular combination

OpenStudy (anonymous):

can you show me an example?

OpenStudy (jfraser):

when L = 0, the orbital is a sphere-shape L = 1 the orbital resembles a pair of balloons tied together L = 2 the orbital resembles two pairs of balloons in a 4-leaf clover kind of arrangement

OpenStudy (jfraser):

OpenStudy (jfraser):

as L gets bigger, the shapes get more complicated, but L is only "allowed" to have particular values, based on the particular value of 'n' for that electron

OpenStudy (jfraser):

the range of L is from 0 to (n - 1) so whatever n is, L CANNOT be equal to or greater than n

OpenStudy (anonymous):

( @JFraser sorry I'm taking a while to write back, I'm just trying to learn this //: )

OpenStudy (anonymous):

@JFraser okay i understand, When the numbers get bigger, L becomes more elaborate, but it cannot surpass n-1

OpenStudy (jfraser):

true.

OpenStudy (jfraser):

right there is your answer

OpenStudy (anonymous):

Okay, tell me if this is worded correctly, No matter how much is added onto L, it cannot become as big/bigger than n-1 Does that sound right? @JFraser

OpenStudy (jfraser):

it's not a matter of adding to L until it becomes equal to (n - 1), its an allowable range that includes all whole numbers between zero and (n - 1).

OpenStudy (jfraser):

quantum mechanics isn't the sort of thing that anyone really picks up quickly, it'll take time to get comfortable with it

OpenStudy (anonymous):

Right.... How would you phrase it? @JFraser

OpenStudy (jfraser):

i just did

OpenStudy (anonymous):

to match what its asking? @JFraser

OpenStudy (jfraser):

the question is asking why the set of quantum numbers given is incorrect. Does that explanation answer the question?

OpenStudy (anonymous):

@JFraser omg sorry i didn't see the other thing you answered me sorry !! I was looking at "quantum mechanics isn't the sort of thing that anyone really picks up quickly, it'll take time to get comfortable with it"

OpenStudy (jfraser):

that's basically it. the values of "L" depends on n, and the combination you're given violate the rules for the values of "L"

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!