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Mathematics 19 Online
OpenStudy (bobobox):

Which of the following is the correct graph of the compound inequality 4p + 1 > −11 or 6p + 3 < 39? (1 point) a number line with closed circles at -3 and 6 and shading in between. number line with open dots at -3 and 6 and shading to the right of 6 and to the left of ¨C3. number line with open dot at -2 and at 5 with shading in between. number line with shading everywhere.

OpenStudy (bobobox):

Number four

OpenStudy (bobobox):

anybody?

OpenStudy (anonymous):

Are you able to solve the inequalities for p?

OpenStudy (bobobox):

no this is one thing i cannot do

OpenStudy (anonymous):

What are you confused on with the problem?

OpenStudy (anonymous):

OK. Take the first one, 4p + 1 > -11. You must isolate p by itself. How would you get rid of the +1 on the left side?

OpenStudy (bobobox):

would you subtract 1 from both side

OpenStudy (texaschic101):

yes

OpenStudy (anonymous):

Excellent. What does that leave you with?

OpenStudy (bobobox):

3p and -12?

OpenStudy (anonymous):

The right side is correct. But when you subtract 1 from the left side you get\[4p+1-1\]which simplifies to 4p. Get it?

OpenStudy (bobobox):

oh yeah

OpenStudy (anonymous):

OK. Now you have\[4p >-12\]How would you get rid of the 4?

OpenStudy (bobobox):

subtract four from both sides so its p>-8

OpenStudy (anonymous):

Not exactly. What mathematical operation (+,-,*,/) is happening between the 4 and the p?

OpenStudy (bobobox):

multipliction

OpenStudy (anonymous):

Right. So, to "undo" a multiplication, do the inverse operation which is...

OpenStudy (bobobox):

division!!!! omg!!! I smart!!!

OpenStudy (anonymous):

You bet! So, to "undo" a multiplication by 4, you would divide both sides by 4. What do you get?

OpenStudy (bobobox):

p>3??

OpenStudy (anonymous):

What about the negative sign on the right hand side? -12/4 = ?

OpenStudy (bobobox):

oh yeah... p>-3?

OpenStudy (anonymous):

Terrific. Now you have to go through similar steps to solve the other inequality for p. Give it a try and tell me what you get. You're doing great!

OpenStudy (bobobox):

p<30 ......

OpenStudy (bobobox):

@ospreytriple

OpenStudy (anonymous):

Almost. First subtract 3 from both sides to give\[6p < 36\]. Now you have to divide both sides by 6. What do you get when you do that?

OpenStudy (bobobox):

p<6

OpenStudy (anonymous):

That's it. The hard part is done. Now you have\[p > -3 \text{ and } p < 6\]. Which graph shows this?

OpenStudy (bobobox):

This is another part i have no clue about

OpenStudy (anonymous):

OK. So you know that p has to be between -3 and 6. On the answer sheet, you're looking at the part of the number line in blue. Which one is blue from -3 to 6?

OpenStudy (bobobox):

the first one

OpenStudy (anonymous):

Sorry. I messed up. The correct answer could be either in blue or in yellow. The first one is a great choice, but there is one small problem. You have to look at the ends of the line. If the circles are filled in (solid dots), it means that that point is considered to be part of the line. In the first one the end points are solid, meaning those points are included. What that looks like mathematically is \[p \ge -3 \text{ and } p \le 6\]And that's not the solution you got. If the endpoints are not to be included, you must choose end points that are hollow (little circles). Does all this make sense?

OpenStudy (bobobox):

No im sorry I need help I have 1/3 question I had answered and I need help because Ive been on this site for two hours @ospreytriple

OpenStudy (anonymous):

OK. Your solution is that p must be greater than -3 and it must also be less than 6. So p=3 and p=6 are not part of your solution. This sound OK?

OpenStudy (anonymous):

Because 3 and 6 are NOT part of your solution, you're looking for the graph that has little circles at 3 an 6, meaning they're not included. Can you find that graph?

OpenStudy (bobobox):

hold on

OpenStudy (bobobox):

is it the third one?

OpenStudy (anonymous):

Looks to me like the little circles in the third one are at -2 and 5. If that's true, this is not the one you want.

OpenStudy (bobobox):

thats not true

OpenStudy (anonymous):

I've been looking at the other question on your screenshot. It looks like they are using a different convention than I am used to for the end points of the line segment. Looks like they use solid dots if the point IS NOT included and hollow circles if the point IS included. You'll have to confirm that by looking in your book. But, in that case, you were correct in choosing the first answer as the correct one. Sorry for the confusion, but sometimes things are different in different books.

OpenStudy (bobobox):

okay see these things i dont know either!

OpenStudy (bobobox):

oh wait i was looking at the wrong one you were right

Directrix (directrix):

The inequality being graphed is p<6 OR p> -3 . I think you may be graphing p<6 AND p> -3 . That is not the same as p<6 OR p> -3 . Look again. I think the correct graph is shown.

OpenStudy (anonymous):

Doesn't the term compound inequality imply both inequalities must by satisfied?

OpenStudy (bobobox):

aaaaaaahhhhhh

Directrix (directrix):

Compound means "or" as well as "and."

OpenStudy (anonymous):

Sorry for messing things up then. Well, we got to practice solving a couple of inequalities. Good luck.

Directrix (directrix):

The posted question states: 4p + 1 > −11 or 6p + 3 < 39 @ospreytriple Your work is not wasted.

OpenStudy (bobobox):

help someone

OpenStudy (bobobox):

i need math help please

Directrix (directrix):

p<6 OR p> -3 |dw:1423343052833:dw|

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