Question

Determine the empirical formula for a copound containing 47.09 mass % C, 6.59 mass % H and 46.33 mass % Cl

Answer 1

assume you have 100 grams of the substace. so then that means you have 47.09g of 6.50 g of H and 46.33 g of Cl. convert to moles of each substances

Answer 2

HOw do i convert to moles? I am drawing a blank @TheGoat

Answer 3

lets say for C decided 47.09 by its molar mass because i mole of C equals to its molar mass

Answer 4

divide not decid

Answer 5

and the molar mass is the total mass for the compound correct? @TheGoat

Answer 6

not the compound. the element so for C it is 12.01. The molar mass can be found on the periodic table

Answer 7

so i take 47.09/12.01 @TheGoat correct?

Answer 8

yes

Answer 9

after you convert all of them to moles if the results are not whole number or close to a whole number such as 3.9 then you divide by the smallest number got after converting to moles