You have 0.5 L of air at a pressure of 203 kPa and 70°C in a rigid, sealed container. What is the absolute temperature of the air?
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OpenStudy (daniellelovee):
203 K
OpenStudy (ichliebedich):
the answer is 273.15+70=343.15
OpenStudy (daniellelovee):
that's not an option
OpenStudy (daniellelovee):
70 K
70 K
203 K
273 K
OpenStudy (ichliebedich):
273 i think
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OpenStudy (daniellelovee):
lol the "I think" part Im not so found of :p lets see if @Somy can explain it ^.^
OpenStudy (somy):
i too think so hmmm
OpenStudy (ichliebedich):
i did 343.15-70 i got 273
OpenStudy (somy):
273K = 0 Celsius
OpenStudy (somy):
im guessing absolute temperature is 0 Celsius
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OpenStudy (ichliebedich):
so i was right?
OpenStudy (daniellelovee):
alright that explain thank you both but I can't give 2 medals so can @ichliebedich give a medal to @Somy please? :)
OpenStudy (somy):
' Absolute temperature is the temperature of an object on a scale where 0 is taken as absolute zero. Absolute temperature scales are Kelvin and Rankine. Absolute zero is the lowest temperature at which the system is in a state of lowest possible (minimum) energy.No electronic device can operate at this temperature.'
yep thats right