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Chemistry 16 Online
OpenStudy (daniellelovee):

You have 0.5 L of air at a pressure of 203 kPa and 70°C in a rigid, sealed container. What is the absolute temperature of the air?

OpenStudy (daniellelovee):

203 K

OpenStudy (ichliebedich):

the answer is 273.15+70=343.15

OpenStudy (daniellelovee):

that's not an option

OpenStudy (daniellelovee):

70 K 70 K 203 K 273 K

OpenStudy (ichliebedich):

273 i think

OpenStudy (daniellelovee):

lol the "I think" part Im not so found of :p lets see if @Somy can explain it ^.^

OpenStudy (somy):

i too think so hmmm

OpenStudy (ichliebedich):

i did 343.15-70 i got 273

OpenStudy (somy):

273K = 0 Celsius

OpenStudy (somy):

im guessing absolute temperature is 0 Celsius

OpenStudy (ichliebedich):

so i was right?

OpenStudy (daniellelovee):

alright that explain thank you both but I can't give 2 medals so can @ichliebedich give a medal to @Somy please? :)

OpenStudy (somy):

' Absolute temperature is the temperature of an object on a scale where 0 is taken as absolute zero. Absolute temperature scales are Kelvin and Rankine. Absolute zero is the lowest temperature at which the system is in a state of lowest possible (minimum) energy.No electronic device can operate at this temperature.' yep thats right

OpenStudy (ichliebedich):

yeah thats why i did 343.15-70

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