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OpenStudy (anonymous):
Evaluate log2 1/64
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OpenStudy (alekos):
start by writing 64 to a power of 2
OpenStudy (anonymous):
4096
OpenStudy (alekos):
No. 64 = 2^n
Find n
OpenStudy (anonymous):
8
OpenStudy (alekos):
No, try again
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OpenStudy (anonymous):
dont you square it
OpenStudy (alekos):
64 = 8^2
we're looking for 2^n
OpenStudy (alekos):
How many times do we have to multiply 2 to get 64?
OpenStudy (anonymous):
2 times
OpenStudy (alekos):
No. 2 x 2 x 2 x 2 x 2 x 2 = what
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OpenStudy (anonymous):
64
OpenStudy (alekos):
Thats good. So we have
\[2^{6} = 64\]
Do you follow?
OpenStudy (anonymous):
2^6?
\
OpenStudy (anonymous):
yeah lol
OpenStudy (alekos):
OK so what do you think 1/64 will be, expressed as a power of 2 ?
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OpenStudy (anonymous):
now im confused what arwe you saying
OpenStudy (alekos):
OK. lets try something different
have you seen the rule log(m/n) = log(m) -log(n) ?
OpenStudy (anonymous):
no
OpenStudy (alekos):
this is a basic log rule.
in your original question you had log(1/64) (where log is base 2)
so what do you think that works out to?
OpenStudy (anonymous):
6
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OpenStudy (alekos):
You appear to have no understanding of logarithms and the rules associated with them.
log(1/64) = log(1) - log(64)
OpenStudy (alekos):
using the rule I wrote earlier
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