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Mathematics 20 Online
OpenStudy (anonymous):

Evaluate log2 1/64

OpenStudy (alekos):

start by writing 64 to a power of 2

OpenStudy (anonymous):

4096

OpenStudy (alekos):

No. 64 = 2^n Find n

OpenStudy (anonymous):

8

OpenStudy (alekos):

No, try again

OpenStudy (anonymous):

dont you square it

OpenStudy (alekos):

64 = 8^2 we're looking for 2^n

OpenStudy (alekos):

How many times do we have to multiply 2 to get 64?

OpenStudy (anonymous):

2 times

OpenStudy (alekos):

No. 2 x 2 x 2 x 2 x 2 x 2 = what

OpenStudy (anonymous):

64

OpenStudy (alekos):

Thats good. So we have \[2^{6} = 64\] Do you follow?

OpenStudy (anonymous):

2^6? \

OpenStudy (anonymous):

yeah lol

OpenStudy (alekos):

OK so what do you think 1/64 will be, expressed as a power of 2 ?

OpenStudy (anonymous):

now im confused what arwe you saying

OpenStudy (alekos):

OK. lets try something different have you seen the rule log(m/n) = log(m) -log(n) ?

OpenStudy (anonymous):

no

OpenStudy (alekos):

this is a basic log rule. in your original question you had log(1/64) (where log is base 2) so what do you think that works out to?

OpenStudy (anonymous):

6

OpenStudy (alekos):

You appear to have no understanding of logarithms and the rules associated with them. log(1/64) = log(1) - log(64)

OpenStudy (alekos):

using the rule I wrote earlier

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