Question

An irregular polygon is shown below:

Image of irregular polygon with length of 9 units and height of 4 units labeled on left side. Top side length of 4 units, the side adjacent to it on the right is 2 units.

The area of the irregular polygon is ____ square units. @PRAETORIAN.10 @iambatman @bohotness

Answer 1

Cut it and make two rectangles.

Answer 2

Okay

Answer 3

Therefore giving us a square that is:

Length of 4 * Width of 4

And a rectangle.

To find the length, we subtract 9 - 4

Answer 4

And what's that?

Answer 5

I made another one just in case

Answer 6

5, obviously >.<

Answer 7

Yep, that would work too.

Answer 8

Yes, so the length is 5.

Now to find the width we can subtract 4 - 2

Answer 9

2

Answer 10

wait so, 10 for the length and width?

Answer 11

The length is 5, and the width is 2.

Answer 12

So we have a square with a side length of 2, and a rectangle with a length of 5, and a width of 2.

Find the areas of both and add them.

Area of a Square:

\(A = s^2\)

Where 's' is the length of the side.

Area of a Rectangle:

\(A = lw\)

Where 'l' is the length, and 'w' is the width.

Answer 13

Can you do that? @PoppyGirl63

Answer 14

Sorry, I was checking something. It should be 14, right? @iGreen.

Answer 15

Yep, sounds good to me.

Answer 16

YUS! Thanks for the help.

Answer 17

Np!