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Mathematics 26 Online
OpenStudy (mokeira):

find dy/dx by implicit differentiation

OpenStudy (mokeira):

\[e^ycosx=1+\sin(xy)\]

OpenStudy (mokeira):

I am not sure how to differentiate sin(xy)

OpenStudy (anonymous):

what is differentiation of sin(.) ??

OpenStudy (mokeira):

cos(.)

OpenStudy (mokeira):

is that right?

OpenStudy (anonymous):

Good..

OpenStudy (anonymous):

Then you do the differentiation of .

OpenStudy (anonymous):

\[\frac{d}{dx}(\sin(\color{red}{x})) = \cos(x) \times \frac{d}{dx} (\color{red}x)\]

OpenStudy (anonymous):

\[\frac{d}{dx} (x) = 1\\ so, \; \; \frac{d}{dx}(\sin(x))= \cos(x) \times 1 = \cos(x)\]

OpenStudy (mokeira):

yes

OpenStudy (anonymous):

Similarly do that..

OpenStudy (anonymous):

\[\frac{d}{dx} (\sin(xy)) = \cos(xy) \times \frac{d}{dx}(xy)\]

OpenStudy (mokeira):

oooh now i get it, so will it ultimately be cos x+ cos(xy)d/dx

OpenStudy (anonymous):

Now, here product rule applies..

OpenStudy (anonymous):

wait..

OpenStudy (mokeira):

ok

OpenStudy (anonymous):

Final answer?

OpenStudy (anonymous):

\[d(\sin(xy)) = \cos(xy)[x \frac{dy}{dx} + y]\]

OpenStudy (anonymous):

Is this okay?

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