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If the specific heat of water is 1.0 calorie/gram°C, how many calories are required to raise 500 grams of water 10.0°C? 510 cal 5,000 cal 50 cal 501 cal
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SH= Specific Heat, Q=energy, tf - ti = change in temperature, and M is the mass. All you have to do is plug into the equation below. \[Q=MSH \Delta T\]
500g*1.0calorie/grams*10.0
which equals 5,000 cal
That is correct
oh ok thanks
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