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Mathematics 19 Online
OpenStudy (anonymous):

please someone help me, I'll give medal and fan, pleaseeee

OpenStudy (anonymous):

iz!!

OpenStudy (misty1212):

hello!!

OpenStudy (anonymous):

OpenStudy (misty1212):

lets go g first because it is easy

OpenStudy (misty1212):

the largest cosine can be is 1 so the largest 2 times cosine can be is 2 so the largest 2 times cosine +4 can be is 6

OpenStudy (anonymous):

so I only have to answer for f or g?

OpenStudy (anonymous):

no i think misty meant do g first now we can do f

OpenStudy (anonymous):

pretty much along the same lines of reasoning as \((x-3)^2\geq0\) so \(-4(x-3)^2\leq 0\) and therefor \[-4(x-3)^2+3\leq 3\]

OpenStudy (anonymous):

could you explain it in words? im pretty slow when it comes to this lol

OpenStudy (anonymous):

to recap, the maximum value of \(f\) is 3 the maximum value of \(g\) is 6

OpenStudy (anonymous):

yeah sure

OpenStudy (anonymous):

\((x-2)^2\) is a square and a square is never negative

OpenStudy (anonymous):

that means it is always greater than or equal to zero

OpenStudy (anonymous):

when you put a minus sign in front, that means it is always less than or equal to zero

OpenStudy (anonymous):

when you add 3 out at the end, that means it is always less that or equal to 3

OpenStudy (anonymous):

wait... im so confused. so for f(x) we can say that because the negative and the minus sign, it changes its value to greater? @satellite73

OpenStudy (anonymous):

@Directrix @sleepyjess

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