find the points of intersection of the parabolas y=1/2x^2 and y=1-1/2x^2. Show that at each of these points the tangent lines to the 2 parabolas are perpendicular. Thanks!

Question

anonymous · Answer

the intersection when y =1/2x^2=y=1-1/2x^2

anonymous · Answer

tangent means the slope which is the derivative of the function

anonymous · Answer

pertpendicular..... slope1*slope2=-1

anonymous · Answer

i dont know what is a derivative. i just start calculus this semester, and we're starting on change of limits.

anonymous · Answer

ok

anonymous · Answer

y=mx+b

anonymous · Answer

plug x value (intersection) to the function y=1/2 x^2

anonymous · Answer

i dont sure where to get the x value

anonymous · Answer

m = $$m = \frac{ Y _{2} - Y _{1} }{ X _{2} - X _{1} }$$

anonymous · Answer

yes...

anonymous · Answer

The best thing you can do is to go Read that section in your book, carefully. That's what I always do, and find the answers for myself.

campbell_st · Answer

I think the 1st task should be to find the points of intersection

so 

$$\frac{1}{2} x^2 = 1 - \frac{1}{2} x^2$$

just so you know the points you need.

campbell_st · Answer

and I'd recommend graphing the 2 curves... to help you understand what is happening...

anonymous · Answer

okay...

sissyedgar · Answer

... :)