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Evaluate the double integral y^2/(x^2+y^2)dA, where R is the annular region bounded by the circles x^2+y^2=1 and x^2+y^2=2.
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familiar with double integrals in polar coordinates ?
There is a Explaination for this and it is awesome
Yes.
Rewrite in terms of r. x = rcos(theta) y = rsin(theta) x^2 + y^2 = r^2
Instead of x and y, your two integrals will be the radius and the angle. Your radius in this equation goes from 1 to 2.
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Your angle of rotation is from 0 to 2Pi. So the bounds for your double integral will be: dr = 1 to 2 dtheta = 0 to 2pi
Simple integration from there.
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