Question

Please help

Find the value of x so that the line containing (4, 8) and (2, -1) is
perpendicular to the line containing (x, 2) and (-4, 5). Graph the lines.

Answer 1

How do i solve this step by step?

Answer 2

sorry but i don't know how to solve that step by step

Answer 3

first you get the equation of the line containing (4, 8) and (2,-1)...

Answer 4

you are given two points already so you can plot the line....

Answer 5

ok, so the slope for that line would be 9/2

Answer 6

and then the slope for the second line would be -2/9 right?

Answer 7

yup

Answer 8

yes of course

Answer 9

so then what would i do to find x?

Answer 10

what would be the equation of the first line?

Answer 11

you can determine it using point-slope formula...

Answer 12

so y-8 = 9/2(x-4)

Answer 13

would that be the equation for the first line?

Answer 14

actually would the end part be (x-(-4)

Answer 15

yup better to write it in standard form.... Ax + By + C = 0

Answer 16

how would i do that?

Answer 17

simplify your equation...

Answer 18

A, B, and C are constants...

Answer 19

y-8 = 9/2 (x-4)
2y-16=9x-36
9x-2y-36+16=0
9x-2y-20=0

Answer 20

for the second line... it would be Bx + Ay + D=0

Answer 21

in line1: A=9, B=-2, C=-20
for line2: A=-2, B=9, D still unknown...

Answer 22

hmmmm I am a bit lost, I'll just go and ask my teacher tomorrow

Answer 23

thanky ou fr trying though!

Answer 24

line2 is -2x+9y+D=0

Answer 25

you don't want to continue?

Answer 26

we're almost there....

Answer 27

no, it is ok! Sorry for wasting your time :(

Answer 28

the coefficients A and B for perpendicular lines are interchangeable...

Answer 29

that is a rule...

Answer 30

ok if that's what you want... :)