Question

Hi, I am having trouble creating a 4th degree polynomial having 2 real zero's. Can anyone help please?

Answer 1

it this 4th grade

Answer 2

No Algebra 2 11 grade.

Answer 3

Can you help?

Answer 4

yeah I can help

Answer 5

Ok cool so what do I do first?

Answer 6

I need to choose 2 numbers and go off of those right?

Answer 7

yes

Answer 8

Ok so how about 6 and 12?

Answer 9

or 2and 4?

Answer 10

what is the question I ant help you if there's not a question :)

Answer 11

Mrs.Collons is at the table with you and she explains that 4th degree polynomials have 4 real zero's. She asks you if it is possible to create a 4th degree polynomial with 2 real zero's. Demonstrate how to do this and explain steps.

Answer 12

ok so first you need to know how to do a 4th degree polynomials and then explain the steps and demonstrate... can you do that ?

Answer 13

I think so.. You want to walk with me through it real to make sure?

Answer 14

I can go off of x-2 x+5 right?

Answer 15

I don't know what I can walk you thourgh but you can ask @Godlovesme but I can help you with the rest :))))))

Answer 16

Do you know whats first?

Answer 17

no sorry :(( it would take while to help you

Answer 18

How do I ask? I just signed up for openstudy

Answer 19

just @ the the persons name..... for instants @SoccerQueen97

Answer 20

OK thanks I guess I will get back to you whenever. thank you :)

Answer 21

@Godlovesme can you help?

Answer 22

and to give a medal just press the best response button and to fan click on the person and fan and ur wlcm

Answer 23

@SoccerQueen97 needs help @roses_red.

Answer 24

@ayanna1100 Do you know someone who can help that is online?

Answer 25

YESs please.

Answer 26

I to have algebra 2 I'm in 11th grade as well

Answer 27

Thats cool. it totally blows right now lol
Do you have FLVS?

Answer 28

That s fine on somethings i can help you and what is that (FLVS)?

Answer 29

Florida Virtual School.
I need to explain how to create a 4th degree polynomial with 2 real zero's

Answer 30

I can help

Answer 31

Yay awesome

Answer 32

So whats first, I need to have to numbers right to start from.

Answer 33

2*

Answer 34

does it matter what the numbers are?

Answer 35

does the numbers have to be the ones you showed on top?

Answer 36

@SoccerQueen97 say the two zeroes you have are 2 and 5. You would first need to make it so f(x)= (x-2)(x-5)

Answer 37

Ok So then I have to distribute right?

Answer 38

yea

Answer 39

yes.

Answer 40

Like x^2 2x and 5x?

Answer 41

yea

Answer 42

You should get x^2-7x+10

Answer 43

Ok so is that the polynomial? How did you get 7x?

Answer 44

that's when you combined your like terms right?

Answer 45

becasue 2x+5x would give you 7x

Answer 46

There's more oh gosh lol

Answer 47

So you added

Answer 48

lml

Answer 49

How'd you know to either subtract and add?

Answer 50

okay when you distribute,,, you have to multiply out each term, then combine like terms. so first you'd do x*x, which is x^2. then you do x*-5 and you get -5x. then x*-2 and you get -2x and then -2*-5 which is 10. so you have x^2-5x-2x+10. when you combine the two middle terms you get -7x

Answer 51

what do you mean? @SoccerQueen97

Answer 52

NVM. Oh ok that helps out a lot thank you so much you guys.

Answer 53

i knew i was right, and she saying how did we get 7x but you just explained it so she should get it now

Answer 54

we're not done yet, though

Answer 55

You needed a 4th degree polynomial... that's only two.

Answer 56

The question just wants to know about having just 2 real zero's

Answer 57

I forgot i thought she said 2

Answer 58

yeah, but you need a 4th degree polynomial, correct?

Answer 59

yes she does which means you would need to find out the other part in order to have a 4 degree polynomial am I right
?

Answer 60

Here I will put in the question.

Answer 61

Mrs.Collons is at the table with you and she explains that 4th degree polynomials have 4 real zero's. She asks you if it is possible to create a 4th degree polynomial with 2 real zero's. Demonstrate how to do this and explain steps.

Answer 62

okay, to get the 4th degree polynomial, you need to do (x^2-7x+10)^2 which is (x^2-7x+10)(x^2-7x+10)

Answer 63

then you will get the polynomial to the 4th degree because the first term will then be to the 4th power

Answer 64

Is that with real zero's?

Answer 65

2*

Answer 66

yes

Answer 67

OK thank you so much. This really helped a lot.

Answer 68

you'd get the 2 same real zeroes, but they'll have a multiplicity of 2

Answer 69

Thank you:)

Answer 70

let me know what you get, and I'll check it for you

Answer 71

and no problem. I love math :)

Answer 72

So the first one is x^4 then 14x then 20?

Answer 73

I forget how to set it up.

Answer 74

okay. first multiply the x^2 by all of the terms in the second ( )

Answer 75

let me know what you get.

Answer 76

x^4 7x2 10x

Answer 77

??

Answer 78

close, but the degrees are off. remember, it's an x^2.... not just an x. you SHOULD get x^4-7x^3+10x^2

Answer 79

do you understand how I got that?

Answer 80

I think so. I can't forget about the ^2 in x^2 is what you mean right? I can't just add an x to it.

Answer 81

yeah. so next you'll do the same process but with the middle term (-7x)

Answer 82

More? gosh this crazy. lol.

Answer 83

haha XD don't get too overwhelmed. you're almost done.

Answer 84

Ok lets do this then. What did you mean by doing the middle term?

Answer 85

distribute the middle term (-7x) like how you did with the first term... to each term in the second ( )

Answer 86

Oh ok so it would be ...idk sorry I am having so much trouble.

Do I distribute it to x^4 too?

Answer 87

you'd do -7x*x^2, -7x*-7x, -7x*10

Answer 88

make sense?

Answer 89

Ill try give me a sec

Answer 90

how's it coming along? @SoccerQueen97

Answer 91

:(

Answer 92

not good?

Answer 93

okay, so when you distribute the -7x, you get -7x^3+49x^2-70x

Answer 94

so far, you should have x^4-7x^3+10x^2-7x^3+49x^2-70x

Answer 95

make sense? you're ALMOST done. now you need to distribute the last term (10)

Answer 96

Into the one you just did right?

Answer 97

no. into the last ( ). you always work from the original. so basically you're just doing 10(x^2-7x+10)