Question

For the reaction 4NO2 (g) + O2 (g) -> 2N2O (g)

a) Write an expression for the rate of change of NO2 in terms of O2.

b) Write an expression for the rate of change of N2O5 in terms of NO2.

Show step-by-step, and I'll reward you w/ a trophy!

Answer 1

Rate = k[A]\(\sf ^x\)[B]\(\sf ^y\)
where A and B are your reactants

Answer 2

A trophy for me won't help you learn this material, as i have already learned this before.

Answer 3

This isn't a rate law question, per se. The rate of change of NO2 needs to be expressed in such a way to show that the rate of decrease of NO2 is four times greater than the rate of decrease of O2. i.e.,\[\color{green}{\dfrac{-\Delta [\text{NO}_2]}{\Delta t} = \dfrac{-4\Delta [\text{O}_2]}{\Delta t} }\]