Question

Integral Help :)

Answer 1

\[\int\limits_{}^{}(zdz)/(\sqrt{z-2})\]

Answer 2

I set u as z-2....

Answer 3

seems like a good idea

Answer 4

\[\int\limits\limits_{}^{}(u+2)du * 1/\sqrt{u}\]

Answer 5

So you would get something like that?

Answer 6

maybe
\[\int\frac{u+2}{\sqrt{u}}du\]

Answer 7

rewrite in two pieces with exponents, use the backwards power rule

Answer 8

Hmmm? I don't understand

Answer 9

\[\int\limits_{}^{}\frac{u}{\sqrt{u}}+\frac{2}{\sqrt{u}}~du\]