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Mathematics 16 Online
OpenStudy (anonymous):

Situation: a 25 gram sample of a substance that’s used for drug research has a K-value of 0.1205. N=N0e^-kt N0(zero)= initial mass(at time t=0) N= mass at time t K= a positive constant that depends on the substance itself and on the units used to measure time t= time, in days Find the substances half-life, in days. Round your answer to the nearest tenths????

OpenStudy (ribhu):

i'll help u out with this.

OpenStudy (ribhu):

@brittany.hodges see, half life is that time when the concentration or mass becomes exactly half of which was taken initially.

OpenStudy (anonymous):

sorry but i still dont get it and i took notes like 30 times :/ @ribhu

OpenStudy (ribhu):

you have to be patient and with open mind, i bet i will make u understand.

OpenStudy (ribhu):

example if I take 1 gm of material and know that it will be left 0.5 gm at t=30 minutes so the half life would be 30 minutes. @brittany.hodges you have to stay with me here attentive.

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

@ribhu

OpenStudy (ribhu):

so lets discuss ur problem.

OpenStudy (anonymous):

okay go ahead

OpenStudy (ribhu):

understand each and every variable like N, No etc.

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

@ribhu

OpenStudy (ribhu):

since the k value has been given

OpenStudy (ribhu):

as i have already told u that half life would have the units same as time. so here in your question they are asking nothing but

OpenStudy (ribhu):

in what time the mass of sample decreases to 12.5 gm (since initial mass is 25gm)

OpenStudy (ribhu):

@brittany.hodges are u getting it? any doubt u have?

OpenStudy (ribhu):

is my method fine with u ? @brittany.hodges

OpenStudy (ribhu):

Now substituting the values N=12.5 (at time t=t, here half life. ) No = 25 k= 0.1205 now its simple exponential equation where you need to calculate t.

OpenStudy (ribhu):

@brittany.hodges are u listening.

OpenStudy (anonymous):

yes im trying to rap my finger around it sorry

OpenStudy (anonymous):

@ribhu

OpenStudy (ribhu):

now did u get what i explained.

OpenStudy (anonymous):

yes im trying to plug it into the equation

OpenStudy (ribhu):

the method you must have got and concept of half life must have been cleared to u. @brittany.hodges

OpenStudy (anonymous):

i got t= 5.75225876

OpenStudy (anonymous):

@ribhu

OpenStudy (ribhu):

exactlyyyy

OpenStudy (anonymous):

yeah so after that i just plug it into the equaion and solve it?

OpenStudy (ribhu):

was i of help to you, probably better than ur notes. lol

OpenStudy (anonymous):

yeah thanks

OpenStudy (ribhu):

yeah thats it. or other wise one method is that \[No/2 = No e^-kt\]

OpenStudy (ribhu):

take ln both the sides and then the equation reduces to \[\ln 2 / k\]

OpenStudy (ribhu):

this formula is always valid for these kind of question to calculate the half lives.

OpenStudy (anonymous):

okay thanks for all the help

OpenStudy (ribhu):

i hope i made it clear to u.

OpenStudy (ribhu):

@brittany.hodges

OpenStudy (ribhu):

are u sure u are clear with this? @brittany.hodges

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