Situation: a 25 gram sample of a substance that’s used for drug research has a K-value of 0.1205. N=N0e^-kt N0(zero)= initial mass(at time t=0) N= mass at time t K= a positive constant that depends on the substance itself and on the units used to measure time t= time, in days Find the substances half-life, in days. Round your answer to the nearest tenths????
i'll help u out with this.
@brittany.hodges see, half life is that time when the concentration or mass becomes exactly half of which was taken initially.
sorry but i still dont get it and i took notes like 30 times :/ @ribhu
you have to be patient and with open mind, i bet i will make u understand.
example if I take 1 gm of material and know that it will be left 0.5 gm at t=30 minutes so the half life would be 30 minutes. @brittany.hodges you have to stay with me here attentive.
okay
@ribhu
so lets discuss ur problem.
okay go ahead
understand each and every variable like N, No etc.
yes
@ribhu
since the k value has been given
as i have already told u that half life would have the units same as time. so here in your question they are asking nothing but
in what time the mass of sample decreases to 12.5 gm (since initial mass is 25gm)
@brittany.hodges are u getting it? any doubt u have?
is my method fine with u ? @brittany.hodges
Now substituting the values N=12.5 (at time t=t, here half life. ) No = 25 k= 0.1205 now its simple exponential equation where you need to calculate t.
@brittany.hodges are u listening.
yes im trying to rap my finger around it sorry
@ribhu
now did u get what i explained.
yes im trying to plug it into the equation
the method you must have got and concept of half life must have been cleared to u. @brittany.hodges
i got t= 5.75225876
@ribhu
exactlyyyy
yeah so after that i just plug it into the equaion and solve it?
was i of help to you, probably better than ur notes. lol
yeah thanks
yeah thats it. or other wise one method is that \[No/2 = No e^-kt\]
take ln both the sides and then the equation reduces to \[\ln 2 / k\]
this formula is always valid for these kind of question to calculate the half lives.
okay thanks for all the help
i hope i made it clear to u.
@brittany.hodges
are u sure u are clear with this? @brittany.hodges
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