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Mathematics 16 Online
OpenStudy (adamaero):

System of eq help - MEDAL [1] 0 = xcos30 - ycos45 [2] 0 = xsin30 + ysin45 - 9.81*m [1] x = ycos45/cos30 substitution 0 = (sin30)ycos45/cos30 + ysin45 - 9.81*m 0 = y(-.299) - 9.81*m ...what happened?!

OpenStudy (adamaero):

OpenStudy (anonymous):

Where you want help?

OpenStudy (anonymous):

Reduce your equations a little bit from Trigonometry..

OpenStudy (anonymous):

\[\frac{\sqrt{3}}{2}x - \frac{1}{\sqrt{2}}(y) = 0 \implies \sqrt{3} x - 2y = 0\]

OpenStudy (anonymous):

\[\frac{\sqrt{3}}{2}x - \frac{1}{\sqrt{2}}(y) = 0 \implies \sqrt{3} x - \sqrt{2}y = 0\]

OpenStudy (anonymous):

\[\frac{1}{2}x + \frac{1}{\sqrt{2}}y - 9.81m = 0 \implies x + \sqrt{2}y = 9.81m\]

OpenStudy (anonymous):

Add both the equations, you will get \(x\) as : \[(\sqrt{3} + 1)x = 9.81m \\ x = \frac{9.81m}{\sqrt{3} +1}\]

OpenStudy (adamaero):

But that's 3.59, not 7.18

OpenStudy (anonymous):

Yes, that is wrong written there.

OpenStudy (anonymous):

Good.. :)

OpenStudy (adamaero):

Wait, the answer book is wrong?

OpenStudy (solomonzelman):

\(\large\color{black}{ \displaystyle 0 = x\cos(30) - y\cos(45) }\) \(\large\color{black}{ \displaystyle 0 = x\sin30 - y\sin(45) }\) cos(45)=sin(45), do you know that?

OpenStudy (solomonzelman):

I don't know what the other 9.81m is

OpenStudy (solomonzelman):

what is 9.81m supposed to be? is that another constant at the end, or what? You want me to solve for 3 variables in only 2 equations? I am not that good at math-:(

OpenStudy (solomonzelman):

the attachement?

OpenStudy (solomonzelman):

yes, so I guess your answer is in terms of m.

OpenStudy (solomonzelman):

So, that means that the coefficients of y are equivalent. \(\large\color{black}{ \displaystyle 0 = x\cos(30) - y\cos(45) }\) \(\large\color{black}{ \displaystyle 0 = x\sin30 - y\sin(45) }\) for convenience, I will multiply the first eq. times -1, \(\large\color{black}{ \displaystyle 0 = -x\cos(30) + y\cos(45) }\) \(\large\color{black}{ \displaystyle 0 = x\sin30 - y\sin(45)-9.81m }\)

OpenStudy (solomonzelman):

Now, add the equations

OpenStudy (solomonzelman):

your y's will go away, because SOMETHING - SOMETHING =0

OpenStudy (adamaero):

0 = x(sin30 - cos30) - 9.81m 9.81m = x x = -26.8

OpenStudy (adamaero):

with m

OpenStudy (solomonzelman):

sin(30) is not the same thing cos(30)

OpenStudy (solomonzelman):

oh, weauit

OpenStudy (solomonzelman):

\(\large\color{black}{ \displaystyle 0 = -x\cos30 +x\sin30 - 9.81m}\) \(\large\color{black}{ \displaystyle 0 = -x(\cos30 -\sin30) - 9.81m}\) \(\large\color{black}{ \displaystyle 0 = -x(\frac{\sqrt{3} }{2} -\frac{1 }{2}) - 9.81m}\) \(\large\color{black}{ \displaystyle 0 = -x(\frac{\sqrt{3}-1 }{2}) - 9.81m}\)

OpenStudy (solomonzelman):

and on...

OpenStudy (adamaero):

0 = -0.366x - 9.81m x = 26.8m ? How is the answer for x, 7.18 then?

OpenStudy (solomonzelman):

\(\large\color{black}{ \displaystyle \frac{-9.81m}{\frac{\sqrt{3}-1 }{2}} = x }\) \(\large\color{black}{ \displaystyle \frac{-19.62m}{\sqrt{3}-1 } = x }\) times sqrt(3)+1 on top and bottom \(\large\color{black}{ \displaystyle \frac{-19.62m(\sqrt{3}+1)}{3-1 } = x }\) \(\large\color{black}{ \displaystyle \frac{-19.62m(\sqrt{3}+1)}{2 } = x }\) \(\large\color{black}{ \displaystyle -9.81m(\sqrt{3}+1) = x }\)

OpenStudy (solomonzelman):

this is what I am getting

OpenStudy (solomonzelman):

I am not very good, or let me put it differently, I am really bad at science. This math question although is math, I don't really get the science side where it is coming from.... (not that I am good at math, either)

OpenStudy (adamaero):

so I should intentionally get it wrong?

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