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Algebra
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solve the given equation log2x=4
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2
2 * ? = 4
-16 c. 8 16 d. 4
it 2 because 2x2=4
but if the chooses are -16 8 16 or 4
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raise both sides are powers of the base, its one of the 1st log laws if \[\log_{a} (x) = b~~~~then~~~~~ a^{\log_{a}(x)} = a^b~~~so~~x = a^b\]
so in your question you have a = 2 and b = 4
looking at the choices... you can eliminate -16 as you can't take the log of a negative.
\[\log_{2} x=4\]
@campbell_st could you help out here after wards http://openstudy.com/updates/54dcf719e4b0b0ad8853e8cf
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my bad i am new and i did not know that there way the equation that i could do
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