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A gas in a rigid container is heated so that its Kelvin temperature doubles. What happens to its pressure? Select one: a. Nothing b. It doubles c. It quadruples d. It is halved
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\[PV= nRT \]since the q is about pressure, lets make P as subject of this formula \[P = \frac{ nRT }{ V }\] so the gas was heated till T became 2T \[P = \frac{ nR2T }{ V }\]
which means upper part of the fraction is doubled while lower part is same as was so what do you think will happen to pressure?
i think b ??
bingo!
thanks you @somy
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