3 Ba+Al(SO4)3=2Al+3BaSO4
if you have 2 moles of BA and 1/2 mole of Al2(SO4)3 what is the access reactant. I just need the formula really quick

Question

3 Ba+Al(SO4)3=2Al+3BaSO4 
if you have 2 moles of BA and 1/2 mole of Al2(SO4)3 what is the access reactant. I just need the formula really quick

anonymous · Answer

@aaronq could I possibly get this formula real quick?

aaronq · Answer

when you wanna find the limiting reactant, you simply divide the moles of each reactant by their respective stoichiometric coefficient. I like to call the "normalized" moles - statistically speaking.

so the formula would be: $\sf Normalized~moles=\dfrac{moles~A}{A's~coefficient}$

then you compare the two, which ever has less moles after the division is the limiting reactant.

anonymous · Answer

OKay. Thanks!

aaronq · Answer

no problem