A particle moves along the curve y = 5x2 – 1 in such a way that the y value is decreasing at the rate of 2 units per second. At what rate is x changing when x = 1?
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@welshfella
@ganeshie8 @Destinymasha @e.mccormick @EclipsedStar @Directrix plz help :)
at what rate y is changing i guess ur question needs correction @mathrulezz
haha sorry i think they posted it on my website wrong :) but yes i guess that's what they mean :)
rate of change = slope of the given function = derivative.
okay so i have 2 find the derivatiev ? :)
at each time interval, you're going to have a different rate of change.
10x is the derivative :D
Yep, you're finding the derivative.
but it asks at what rate is x changing when x = 1
y' = 10x , what is x when y' = 2 units/sec?
1/5 :) thanku!
so its decreasing?
That's what your problem says :)
graCIAS! thank u so much
No problem
y = 5x^2 dy/dt = 10xdx/dt; rate of change of y is given and you have to calculate rate of change of x at x=1. dy/dt = -2 since it is decreasing. so dx/dt = -1/5. change of rate of x
@Jhannybean i am also correct with this one.
There you go, you are right.
Because y and x are both changing across a curve with respect to time.
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