Question

What are the roots of 4x^2+49=0

±7i/2

±14i

±7i

±3i/7

Answer 1

\[4x^2 +49 = 0 \iff (2x)^2 +(7)^2=0\] SO this can be written in the form of \((a+b)^2\) where a = 2x\(^2\) and b= 7

Answer 2

\[
4x^2 + 49 = 0 \\
4x^2 = -49 \\
x^2 = -\frac{49}{4} \\
x = \sqrt{-\frac{49}{4} } = \sqrt{-1} * \sqrt{\frac{7^2}{2^2}} = ?\\
\]