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MIT 6.002 Circuits and Electronics, Spring 2007
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How do you find the current going thru the capacitor at t > 0
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The current threw an inductor does not change instantaneously, therefore iL @t = 0- = iL @t = 0+ = 16/(3 + 5) = 2 A The voltage across a capacitor does not change instantaneously, therefore vC @t = 0- = vC @t = 0+ = 16 {3/(3 + 5)} V = 6 V
wouldnt the capacitor eventually charge to 16 volts if the switch is in position A for a very long time ?
No, it would only charge to the voltage across the 3 ohm resistor. To DC an inductor acts as a short and capacitor acts as an open.
ok , That helps me a lot . Now I can find the current thru the capacitor. When I was assuming that it was 16 V , my solution was not working out correctly thank you !
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