Question

please check my calc problem!!

Answer 1

i got [-4,4]

Answer 2

@freckles

Answer 3

@jim_thompson5910

Answer 4

I assume you used separable variables?

Answer 5

Did you arrive here? \[\frac{1}{2}y^2=\frac{-1}{2}x^2+C\]

Answer 6

yes

Answer 7

ok, and what did you find as your C value?

Answer 8

sorry OS was lagging 1/2y^2+1/2x^2=C

Answer 9

but given your IV, what does C=?

Answer 10

1/2y^2+1/2x^2

Answer 11

Thatisn't what C equals

Answer 12

C is a constant, it never changes

Answer 13

i dont know :/

Answer 14

ok, seems like your teacher did not explain this very well, check this out http://tutorial.math.lamar.edu/Classes/DE/Separable.aspx

Answer 15

especially since you called this a calculus question

Answer 16

I detest bad teachers...

Answer 17

i just did it again and got my answer, so im going with it