Calculate the pull on the root of a turbine blade due to centrifugal force when the rotor is rotating at 300 rpm, the mass of the blade is .2kg and the radius from the axis of the rotor to the center of gravity of the block is 460mm.

Question

anonymous · Answer

@eliassaab  @Kainui

anonymous · Answer

@iambatman  sir lets continue please

shamim · Answer

Centrifugal force=mv^2/r=m*omega^2*r=?
Given m=.2kg
r=460mm=.46m
Omega=2*pi*n
n=300rpm=300/60hz

shamim · Answer

Feel free to ask for more clarification