Question

calc help!

Answer 1

@jim_thompson5910 @freckles could you explain??

Answer 2

I saw earlier you got

\[\Large \frac{1}{2}x^2 + \frac{1}{2}y^2 = C\]

Answer 3

multiply every term by 2

\[\Large \frac{1}{2}x^2 + \frac{1}{2}y^2 = C\]

\[\Large 2*\frac{1}{2}x^2 + 2*\frac{1}{2}y^2 = 2*C\]

\[\Large x^2 + y^2 = C\]

note: 2*C turns into C because C just represents "Constant" (2 times constant = constant)

Answer 4

now you use the initial condition y(2) = 2

that means we have the point (2,2) on this curve. So x = 2 and y = 2. Use these values to find C

Answer 5

so my final answer would be

Answer 6

what did you get for C?

Answer 7

8

Answer 8

good, so yeah the center of this circle is (0,0) and it stretches from x = -sqrt(8) to x = sqrt(8)

also sqrt(8) = 2*sqrt(8)

Answer 9

you have the correct answer

Answer 10

thanks(:

Answer 11

np