Question

find the inverse of
H(x)= (X+3)^2
with restrictions of ( negative infinity, -3]

Answer 1

H(x)=(x+3)^2
y=(x+3)^2
x=(y+3)^2
(x)^1/2=y+3
y=(x)^1/2-3

Answer 2

f^-1(x)=(x)^1/2-3

Answer 3

hmmm

Answer 4

\[x=(y+3)^2\] solve for \(y\)

Answer 5

start with
\[\pm\sqrt x=y+3\] then
\[y=\pm\sqrt{x}-3\] but since you are on \((-\infty, 3\) it is
\[f^{-1}(x)=-\sqrt{x}-3\]

Answer 6

@satellite73 thank you so much!!