Ask your own question, for FREE!
Mathematics 39 Online
OpenStudy (anonymous):

Find g '(x) for g(x) = sec(2x). a) g '(x) = 2sec^2(2x) b) g '(x) = 2sec(2x) c) g '(x) = 2sec(2x)tan(2x) d) g '(x) = 2tan^2(2x) I think i got: C? i just want someone to check my answer :)

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

i think its c

OpenStudy (jhannybean):

This involves using the chain rule: \(\frac{d}{dx}(\sec(x) \cdot \frac{d}{dx}(x)\)

OpenStudy (anonymous):

2sec(2x)tan(2x)

OpenStudy (anonymous):

c is the answer

OpenStudy (anonymous):

that's what i got too @laetitiacarmel :) and @Jhannybean ok, do u think its correct as C? :)

OpenStudy (anonymous):

yes

OpenStudy (jhannybean):

Do you know your derivatives @mathrulezz ?

OpenStudy (anonymous):

Yeah, chain rule is the way to go, lets look at it, g(x) = sec(2x) g'(x) = sec(2x)tan(2x)*(2x)'

OpenStudy (anonymous):

is someone taking calculus 2?

OpenStudy (anonymous):

Derivative of secx = secxtanx

OpenStudy (jhannybean):

And yes, C looks correct.

OpenStudy (anonymous):

ok thank u guys :)

OpenStudy (anonymous):

I also used prime notation, even though the one Jhanny showed you is the "legit" way, but this is easier to see what's going on especially if you're just starting derivatives.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
MakaylaChuck23: Help wats this
8 hours ago 2 Replies 0 Medals
MakaylaChuck23: uh oh
10 hours ago 1 Reply 0 Medals
Treeko: Pics I took w my friend !
29 minutes ago 7 Replies 2 Medals
Aliciaa: Is anyone elses QC going wack? Mine keeps freezing and stuff
10 hours ago 26 Replies 1 Medal
autumnp: does anyone have bandlab?
13 hours ago 4 Replies 0 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!