Question

A committe of five is to b chosen from six men and eight women. Find how many committees are possible if a particular man must be included?
The answer is715 but i don't understand. @jim_thompson5910

Answer 1

"A committe of five ... a particular man must be included"

so you really have 4 slots left because this particular man must be locked in.

Answer 2

6 men total
6-1 = 5 men left over after that person is locked in

8 women total

so there are 8+5 = 13 people who aren't locked in

there are 4 slots, so you need to compute C(13,4)

Answer 3

Formula:

\[\Large C(n,r) = \frac{n!}{r!(n-r)!}\]

Answer 4

thanks so much

Answer 5

np