Don't know how to do this help for medal
question
Which value of x is NOT in the domain of the function f(x)=\(23)/(11 x-24)? x=____
You cannot divide by zero. So if the denominator 11x-24 were equal to zero, then what must the value of x be?
so 0 is the value of x not in the domain?
try plugging x = 0 into f(x). Do you run into a division by zero error?
no
so x = 0 is a perfectly valid input
x = 0 is part of the domain
you need to solve 11x-24 = 0 for x to get the value of x that makes the denominator zero
24/11
@jim_thompson5910
correct, x = 24/11 is the value that when you plug it into 11x - 24, it turns into 0 causing the division by zero error
to avoid division by zero errors, we kick out any values of x that cause the division by zero errors. So that's why x = 24/11 is not in the domain
Find the domain of f(x) = sqrt(4 x -5)
is it 5?
now you need to make sure that the radicand is never negative
so force it to be either 0 or positive \[\Large 4x - 5 \ge 0\] solve for x
x=5/4??
how do you write it in interval notation?
it's actually \[\Large x \ge \frac{5}{4}\] when you solve for x
and how would that be written in interval notion?
go ahead and write out what you think it looks like and I'll help you from there (if you need any). I want to see how much you know about interval notation.
(0,5/4)
the left most edge of the interval \(\Large x \ge \frac{5}{4}\) is 5/4, agreed?
I don't get it
\[\Large x \ge \frac{5}{4}\] describes all the numbers that are greater than or equal to 5/4
the smallest that x can be is 5/4. It cannot get any smaller. So the left edge is 5/4 x can get as large as it wants, so the right edge is infinity
\[\Large x \ge \frac{5}{4}\] written in interval notation is \[\Large \left[\frac{5}{4},\infty)\right.\]
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