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OpenStudy (sleepyjess):

How many moles of glucose (C6H12O6) are in 5.0 liters of a 2.5 M C6H12O6 solution?

OpenStudy (sleepyjess):

@Australopithecus

OpenStudy (aaronq):

\(\sf \large Molarity =\dfrac{moles~of~solute}{L~of~solution }\)

OpenStudy (anonymous):

2.5 M means that for every litre you have there are two point five moles. That is a universal concept to all matter. So because you have 5 litres of a 2.5 M solution, you just multiply 5 * 2.5.

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