Question

the change in velocity takes place in 10 sec interval. What is the magnitude, the algebraic sign and the direction of the average acceleration in each interval?
At the beginning of the interval a body is moving to the right along the x-axis at 5 ft/sec, and at the end of the interval, it is moving towards the right at 20 ft/sec.

Answer 1

Do you know the formula for average acceleration?

Answer 2

m=(v-u)/t

Answer 3

not sure what those symbols mean but i know it as\[Average accel= v_f-v_i/Deltat\]

Answer 4

so the final velocity which is 20 ft/s - the initial velocity which is 5 ft/s

Answer 5

divided by change in time which is 10 seconds

Answer 6

is deltat the time interval?

Answer 7

yes

Answer 8

so, the answer is 1.5 ft/sec?

Answer 9

yes and since it is getting faster moving in the positive direction that will be the direction of the acceleration too

Answer 10

so if it is decelerating on the same direction the sign will be negative?

Answer 11

Yep and the velocity would go from a higher value to lower one

Answer 12

thanks

Answer 13

No problem 😃

Answer 14

BTW, if the velocity is constant but changing on a different direction, the answer will be zero and at rest? thanks again.

Answer 15

The velocity can't be constant and changing directions. Because just like acceleration velocity depends on direction

Answer 16

the other question says the initial velocity is at 20 ft/sec moving to the left and ends at 20 ft/sec to the right...

Answer 17

well i guess in that case v_initial= -20 m/s and v_final = 20 m/s