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OpenStudy (anonymous):
multiply the first equation straight across by 2, then add, the y terms will go bye bye
OpenStudy (misty1212):
HI!!
OpenStudy (shelby1290):
ok so that would be 2x+6y=0
OpenStudy (misty1212):
yes
OpenStudy (misty1212):
then add in a column
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OpenStudy (shelby1290):
Hi
OpenStudy (shelby1290):
Why do i need to add in a column?
OpenStudy (misty1212):
if you do it you will see why
OpenStudy (misty1212):
what @satellite73 said, the y terms will drop out because \(6y-6y=0\)
OpenStudy (shelby1290):
How do you add in a column....?
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OpenStudy (misty1212):
\[2x+6y=0\\
3x-6y=5\] andd and get \[5x=5\]
OpenStudy (triciaal):
@satellite73 It said by substitution
OpenStudy (anonymous):
there is more than one way to skin a cat
OpenStudy (xapproachesinfinity):
just do it this way lol
OpenStudy (misty1212):
it should be clear what \(x\) is if \(5x=5\) right?
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OpenStudy (shelby1290):
lol that saying though @satellite73
OpenStudy (triciaal):
there are 4 methods used to solve simultaneous equations
OpenStudy (shelby1290):
x=1
OpenStudy (misty1212):
yes
OpenStudy (triciaal):
the directions specifically said to solve by substitution
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OpenStudy (misty1212):
then if \(x=1\) and \(x+3y=0\) that means
\[1+3y=0\] and you can solve that one for \(y\)
OpenStudy (shelby1290):
@triciaal what are we doing incorrectly?
OpenStudy (triciaal):
"Solve by substitution:"
@ shelby1290 not following the directions
OpenStudy (triciaal):
@shelby1290 the question said what method to use
OpenStudy (shelby1290):
bring 1 to the other side....
3y=0-1
3y=1
y=0.333333 lol
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OpenStudy (misty1212):
i would probably say \(-\frac{1}{3}\)
dont forget the minus sing
OpenStudy (shelby1290):
@triciaal I've checked my textbook and the answer is x=1 and y= -1/3
OpenStudy (shelby1290):
yeaaa
OpenStudy (misty1212):
lol "sign"
OpenStudy (triciaal):
whatever method you use will give the same answer
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OpenStudy (misty1212):
or the minus sing too, an nice tune
OpenStudy (shelby1290):
lol sign*
OpenStudy (shelby1290):
But thank you mistyyyy
OpenStudy (misty1212):
*sigh...
OpenStudy (misty1212):
\[\color\magenta\heartsuit\]
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OpenStudy (triciaal):
@shelby1290 as I said before there are 4 different methods that can be used to solve these equations
OpenStudy (shelby1290):
Yes I understand that.
OpenStudy (triciaal):
the is the addition / elimination method where you eliminate one variable when you add the equations
OpenStudy (shelby1290):
Thank you for letting me know
OpenStudy (triciaal):
to use the substitution method let one variable be the subject and use this expression for the variable in the second equation.
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OpenStudy (triciaal):
for example let x = -3y from the 1st equation then use this for x in the 2nd
3x - 6y = 5
3(-3y) -6y = 5
-15y = 5 so y = -1/3
use this value in the expression to get x
x = -3(-1/3) = -1
different method same answer (-1, -1/3)