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\[\lim_{x \rightarrow 0} \frac{ x(1-\cos x) }{ \tan^3x }\]
So far I simplified the denominator to sin^3x/ cos^3x and I have x(1-cos x) cos^3x / sin^3x
first take that x to the denominator and convert one tan to tan(x)/x = 1 . Now the expression left is square term in tanx convert it to sin^2x/cos^2x then convert sin to cos using sin^2x + cos^2x =1 and then use a^2-b^2 = (a+b)(a-b) for (1- cos^2x) term
I don't understand how you took out the x. Did you divide by x? Did you divide the whole equation or both the numerator and the denominator?
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