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OpenStudy (bananas1234):
y varies inversely with x and y = 5 when x = 2.
Which is the inverse variation equation for the relationship?
y=2x
y= x + 2
y = 1/2x
y = 10/x
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OpenStudy (coconutjj):
are the coords (2,5) a points on the inverse equation
OpenStudy (coconutjj):
actually that doesn't even matter... the inverse is equal to the original in this special case
OpenStudy (bananas1234):
|dw:1424324216152:dw|
OpenStudy (coconutjj):
Plug in x and y... there's only one equation that satisfies the values
OpenStudy (bananas1234):
yes, the inverse variation equation witch is f(x) = k/x
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OpenStudy (bananas1234):
so if i put in what they gave me i would get |dw:1424324396761:dw|
OpenStudy (coconutjj):
y= 10/x, since when x=2, y=5...
OpenStudy (bananas1234):
@Nnesha is y = 10/x right?
OpenStudy (bananas1234):
because then i would mutiply 2 times 10 and that would = k
Nnesha (nnesha):
yes right
good job :)
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OpenStudy (bananas1234):
sorry 2 times 5
Nnesha (nnesha):
yes :)
OpenStudy (bananas1234):
thanks
Nnesha (nnesha):
np :)
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