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How do I do this 1/3 log(base5) 12x=2
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\[\frac{ 1 }{ 3 }\log_{5} (12x) = 2\] Is that it?
yes
do i put the 1/3 as an exponent
No, but you do need to get rid of it on the left side. So you can multiply both sides by 3 to cancel it.
but what do you do about the log
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Then you can turn it into an exponent. So after multiplying by 3, you get \[\log_{5}(2x)=6 \] right?
Oops, 12x not 2x
Then you can use these log formulas to change it into exponent form: \[\log_{b}y=x \] means the same thing as \[y=b ^{x}\]
so then it would be \[12x=5^{2}\]
5^6, not 5^2
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(since we multiplied the 2 by 3 to clear the 1/3)
i mean 6th power
oh ok then i got it thank you so much for your help
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