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Mathematics 18 Online
OpenStudy (anonymous):

How do I do this 1/3 log(base5) 12x=2

OpenStudy (anonymous):

\[\frac{ 1 }{ 3 }\log_{5} (12x) = 2\] Is that it?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

do i put the 1/3 as an exponent

OpenStudy (anonymous):

No, but you do need to get rid of it on the left side. So you can multiply both sides by 3 to cancel it.

OpenStudy (anonymous):

but what do you do about the log

OpenStudy (anonymous):

Then you can turn it into an exponent. So after multiplying by 3, you get \[\log_{5}(2x)=6 \] right?

OpenStudy (anonymous):

Oops, 12x not 2x

OpenStudy (anonymous):

Then you can use these log formulas to change it into exponent form: \[\log_{b}y=x \] means the same thing as \[y=b ^{x}\]

OpenStudy (anonymous):

so then it would be \[12x=5^{2}\]

OpenStudy (anonymous):

5^6, not 5^2

OpenStudy (anonymous):

(since we multiplied the 2 by 3 to clear the 1/3)

OpenStudy (anonymous):

i mean 6th power

OpenStudy (anonymous):

oh ok then i got it thank you so much for your help

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