Question

I need help with a question from a project I'm doing. I finished the rest of the assignment but the last question makes no sense to me. It's a simulation lab online but here is the last question.

Answer 1

Place the rider at Point E and start his motion. Point E is 24 meters high. The mass of the rider was given in question 4 as 100 kg. Assume that point B touches the ground. Using the equations and the principle of conservation of energy, determine the rider’s kinetic energy at point B. (Hint: You do not know his velocity at the point, there is another way to figure it out)

Answer 2

Given m=100 kg
h=24m
g=9.8m/s^2

Answer 3

Potential energy at point E
P.E=mgh=?

Answer 4

U know potential energy at point E= kinetic energy at point B=?

Answer 5

Response plz for getting better help!!!

Answer 6

How do you get 9.8?

Answer 7

m=100 kg
h=24m
g=9.8m/s^2
PE = mgh
PE = (100kg)(9.8m/s^2)(24m)
PE = 23520 J
K = 1/2(mv)^2
K = 1/2(24kg)(9.8m/s)^2
K = 1,152.48 J

Answer 8

g=acceleration due to gravity

Answer 9

The value of g is a constant

Answer 10

g=9.8m/s^2

Answer 11

So g is not a velocity

Answer 12

So how do I find out velocity from the info given?

Answer 13

Potential energy at point E=mgh=100*9.8*24=?

Answer 14

Kinetic energy at point B=100*9.8*24=?

Answer 15

So
.5mv^2=100*9.8*24
.5*100*v^2=100*9.8*24
v=?