An object is dropped from 33 feet below the pinnacle atop a 1477-ft building. The height (h) of the object after t seconds is given by the equation h=-16t^2+1444. How many seconds until the object is on the ground?

Question

An object is dropped from 33 feet below the pinnacle atop a 1477-ft building. The height (h) of the object after t seconds is given by the equation h=-16t^2+1444.  How many seconds until the object is on the ground?

anonymous · Answer

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anonymous · Answer

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anonymous · Answer

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anonymous · Answer

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anonymous · Answer

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kendricklamar2014 · Answer

The height is 0 when it hits the ground so we do: h=-16t^2+1444 = 0

kendricklamar2014 · Answer

Which equals: 16^2 = 1,444

anonymous · Answer

ok, so we have to figure out what t is in order for h to be 0?

kendricklamar2014 · Answer

Now we do: t^2 = 1,444/16

anonymous · Answer

is that the next step?

anonymous · Answer

@KendrickLamar2014 are you there??

kendricklamar2014 · Answer

Positive Solution:
T = 38/4 =  19/2 = 9.5 seconds

kendricklamar2014 · Answer

Thats how you solve this problem @Lucinda12345

kendricklamar2014 · Answer

Yes

anonymous · Answer

ok, sorry my computer is super slow

anonymous · Answer

Thanks for the help

kendricklamar2014 · Answer

No Problem