Question

Using the Half Angle Identity find sin13pi/12 (find exact value)

Answer 1

@iGreen plz help!!!

Answer 2

So are you suppose to split this up, to make half angle identities?
If so, show me what ya got

Answer 3

alright @adamaero here is what I got sin(13pi/12) --> (pi+pi/12) -->
-sin(pi/12) --> sqrt(1-cos(pi/6)/2) --> sqrt(1-cos[sqrt(3/2)]/2) --> sqrt(2-sqrt(3/4)) --> sqrt(2-sqrt(3/2))

Answer 4

wouw, just press enter

gtg

@xapproachesinfinity @Luigi0210 @zepdrix

Answer 5

sorry that I made so messy so here is my finaql answer... \[\sqrt{2-\sqrt{3}}/2 \]

Answer 6

what do ya think xapproach?

Answer 7

You must have a lot to say :o

Answer 8

what you did was not half angle identity
\[\sin^2(\frac{13\pi}{12})=\frac{1-\cos (\frac{13\pi}{6})}{2}\]

Answer 9

and 13pi/6 can be written as 2pi+pi/6
and since cos has 2pi period then cos (2pi+pi/6)=cos (pi/6)

Answer 10

oh i was away actually doing something else lol

Answer 11

:P

Answer 12

we both got to cos(pi/6) though

Answer 13

this is the half angle identity :
\[\sin^2\theta=\frac{1-\cos 2\theta}{2}\]

Answer 14

well you definitely get the same answer with other methods
they all work fine

Answer 15

just the question asked you to do it with half angle identity
for anything that gets you to the answer is legitimate

Answer 16

alrighty thanks!

Answer 17

YW