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Mathematics 13 Online
OpenStudy (jhannybean):

So I am trying to find the currents 1 2 and 3... but I am kind of unsure if I am doing this right. I am using Kirchhoff's Current and Loop Laws to find the current across each resistor. The laws are: (1) \(\sf EMF_1\) - \(\sf I_1R_1 +I_2R_2 -EMF_2 =0\) (II) \(\sf EMF_2 - I_2R_2 -I_3R_3 = 0\) (III) \(\sf EMF_1 -I_1R_1 -I_3R_3 =0\)

rvc (rvc):

physics question

OpenStudy (jhannybean):

I am trying to find the current through each wire, and so far I have \[\sf EMF_2 -I_2R_2 -I_3R_3 = 0\]\[\sf I_2 = \frac{-I_3R_3+EMF_2}{R_2}\]

OpenStudy (jhannybean):

More math related.

OpenStudy (jhannybean):

And \(\sf EMF_1 -I_1R_1+I_2R_2 -EMF_2 = 0\) therefore \[\sf I_1 = \frac{I_2R_2 - EMF_2 +EMF_1}{R_1}\]

OpenStudy (jhannybean):

Now I know current 3, \(\sf I_3\) is found by.... \[\sf I_1 +I_2 = I_3\]\[\sf I_3 = \frac{-I_3R_3+EMF_2}{R_2} +\frac{I_2R_2-EMF_2 +EMF_1}{R_1}\]

OpenStudy (jhannybean):

I'm just having problems simplifying this fraction :(

OpenStudy (anonymous):

any circuit diagram??

OpenStudy (jhannybean):

Oh yeah, I will draw it. One minute.

OpenStudy (jhannybean):

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OpenStudy (jhannybean):

Given values: \(\sf R_1: 220 ~ohm ~,~ R_2 = 330~ ohm~,~ R_3 = 390 ~ ohm \) \(\sf V_1 = 9 ~V ~,~ V_2 = 12 ~V\)

OpenStudy (anonymous):

there are two ways to do this ques..one is long..i.e. circuit loop and the other one.. is assume a zero volt battery with R3 and combine them all

OpenStudy (anonymous):

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OpenStudy (michele_laino):

Please here are the equations: \[\begin{gathered} {V_1} - {V_2} = {R_1}{I_1} - {R_2}{I_2} \hfill \\ {V_2} = {R_2}{I_2} + {R_3}{I_3} \hfill \\ \end{gathered} \]

OpenStudy (anonymous):

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