For the function f(t) = (cos√t )/(√t) , find the antiderivative F of f that satisfies the given condition F(pi^2 / 4) = 5.
You could perform a substitution
I'm confused...Why did you post a link to this page?
\[\int\limits_{}^{}\frac{\cos(\sqrt{t})}{\sqrt{t}} dt \] do u=sqrt(t)
never mind, can u just help me?
yes its cosine of sqrt of t
let me know if you need more help after trying that sub
can you pls help I have no clue how to do this. please?
@freckles
\[u=\sqrt{t} \\ \frac{du}{dt}=?\]
do you know how to find the derivative of sqrt(t)?
and remember that is just t^(1/2)
use power rule
derivative would be 1/(2√t )right?
yes
\[u=\sqrt{t} \\ 2 du =\frac{1}{\sqrt{t}} dt \] tried to use this substitution in your integral
okay! I get that part now that you showed, but then what?
i know you have to take the integral but idk integral of what
\[F(t)=\int\limits \frac{\cos(\sqrt{t})}{\sqrt{t}} dt \] replace the sqrt(t) inside the cosine with u replace the 1/sqrt(t) dt with 2 du I'm asking you to use the sub
\[F(t) =\int\limits \cos(\sqrt{t}) \frac{1}{\sqrt{t}} dt \] \[F(t)=\int\limits \cos(u) 2 du =2 \int\limits \cos(u) du\] Can you integrate cos(u) w.r.t. u ?
no.. can u just help me all the way through this problm? i have a hw page full of these type of questions I promise I'll do them all!
so you don't know what function you can take derivative of that will give you cos?
\[( ? )'=\cos(u)\]
sine
yes
sorry i didnt know what u meant
so F(t)=2sin(u)+C where u=sqrt(t)
ok and then?
so thats the antiderivative right?
but idk how to satisfy the other equation!
Well you have an unknown constant C there
use the condition to find it
F(a)=b means you will replace t with a and F(a) with b
can you show me?
let me see you try to plug in the values
replace t with pi^2/4 and F(pi^2/4) with 5 and solve for C
can you show m actually like you did above w/ pictures? not just words becuz its hard for me to uderstand
You aren't willing to try to apply what I said?
im sorry i just... its not that im not willing i have to see it to understand it.
Do you know what we found for F(t)?
so 2sin√(pi^2/4) +c = what?
can you tell me the function so far?
|dw:1424455883300:dw|
well don't forget what that expression equals \[F(t)= 2 \sin(\sqrt{t})+C\]
so then?
you are going to replace all the t's with pi^2/4\[F(\frac{\pi^2}{4})=2 \sin(\sqrt{\frac{\pi^2}{4}})+C\]
And you are given what F(pi^2/4) equals
so replace F(pi^2/4) with 5 since F(pi^2/4)=5
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