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OpenStudy (anonymous):
How many complex roots does 6x^4 + x^3-5 = 0 have?
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OpenStudy (welshfella):
you can use descarte's rule of signs to find this. I cant remember the detail I'm afraid...
OpenStudy (anonymous):
I know it has something to do with the greatest power, and the constant.
OpenStudy (welshfella):
one root is -1 so there's possibly 2 complex roots
OpenStudy (anonymous):
find p/q , use synthetic to compress the polynomial until power 2, then use quadratic to solve. Hope it helps
OpenStudy (anonymous):
I thought the same thing too, it only gives my the choices 3, 4, 5, and 6
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OpenStudy (welshfella):
? - i thought you could only have complex roots in pairs...
OpenStudy (welshfella):
-1 is definitely a root
OpenStudy (welshfella):
the greatest power is 4 so there's a total of 4 roots
OpenStudy (anonymous):
thanks for the help guys
OpenStudy (welshfella):
do 5 and 6 cannot be correct
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Directrix (directrix):
For review:
OpenStudy (welshfella):
with Descarts rule you count the changes of sign as you go from left to right in the polynomial
there is one change in this one
OpenStudy (welshfella):
my guess would be 2 real roots and 2 complex
OpenStudy (anonymous):
thank you for all your help
OpenStudy (welshfella):
yw
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