Question

help me I cant figure this out!
f'(x) = 3x^2 - 6x + 2. The point (1,11) lies on y = f(x).

Answer 1

what do you want to do

Answer 2

question?

Answer 3

I'm assuming you want to find f(x)
given f'(x)

Answer 4

So you're given the equation of a tangent line and a point that lies on the curve where that tangent line may intersect?

Answer 5

that's not really a tangent line, it is slope of f at any given x

Answer 6

at this stage we cannot help you out with anything if you don't write your question

Answer 7

do we help to write your question? lol

Answer 8

f'(x) = 3x^2 -6x+2
\(\color{red}{Does}\) the point (1,11) lie on y = f(x)?

Answer 9

Hints:
dy/dx=f'(x)=3x^2-6x+2
\(\int f'(x)dx=f(x)+C\)
use (1,11) to evaluate C.