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Mathematics 24 Online
OpenStudy (anonymous):

At what values of x, does f(x) = 0?

OpenStudy (anonymous):

OpenStudy (campbell_st):

find the x values where the curve cuts the x-axis... that is where f(x) = 0 or y = 0 hope it helps

OpenStudy (anonymous):

I don't understand what you mean.

OpenStudy (adi3):

0 because anything multiplied by zero is zero

OpenStudy (anonymous):

that's the only point?

OpenStudy (adi3):

yup

OpenStudy (adi3):

x = 0, y = 0

OpenStudy (anonymous):

I don't think that's it. There's 6 answer choices.

OpenStudy (anonymous):

-2, 1, 0 -4, 3, 8

OpenStudy (anonymous):

You have to pick all that apply

OpenStudy (adi3):

what class is that

OpenStudy (adi3):

grade

OpenStudy (anonymous):

algebra 2

OpenStudy (adi3):

is it 9th

OpenStudy (anonymous):

9th what?

OpenStudy (adi3):

grade

OpenStudy (anonymous):

like Freshman math?

OpenStudy (adi3):

yes

OpenStudy (anonymous):

umm I guess it would be junior math

OpenStudy (adi3):

okay. Wait let me see the graph firs

OpenStudy (campbell_st):

ok... the task is to find the values of x, that make the function f(x) = 0 these x values are where the curve cuts the x axis... any point on the x axis is (x, 0) so f(x) = 0 for some value x.

OpenStudy (adi3):

I think it is -2, 1, 3 because the value of x is already given.

OpenStudy (campbell_st):

you are asked to identify the specific values...

OpenStudy (anonymous):

so 1, -2, and 3?

OpenStudy (adi3):

yes, because the value of x is already give

OpenStudy (adi3):

1, -2, 3

OpenStudy (campbell_st):

so what do you notice about the y value at each of the points you mentioned..?

OpenStudy (anonymous):

they are 0

OpenStudy (campbell_st):

correct... so these are the points that make y = 0 or f(x) = 0 the vertical axis can be called the y axis or labelled f(x)...

OpenStudy (adi3):

f(x) is is also known as y and y value is 0 and x is given as 1, -2 ,3

OpenStudy (anonymous):

how come 0 doesn't work?

OpenStudy (campbell_st):

because for x = 0 then y would need to be zero... does the curve pass through the origin..?

OpenStudy (adi3):

because it is (1,0) so 1 is x and 0 is f(x)/y

OpenStudy (campbell_st):

the y-intercept is found by letting x = 0.... looking at the curve the y-intercept is y = 6 or the point (0, 6)

OpenStudy (adi3):

campbell_st is right

OpenStudy (anonymous):

Awesome I got it right

OpenStudy (anonymous):

thanks guys

OpenStudy (adi3):

I was wrong.

OpenStudy (campbell_st):

basically for any curve x- intercepts called zeros or roots.... let y = 0 y- intercept let x = 0

OpenStudy (adi3):

okay.

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