a funnel 0.24m in diameter at the top and 24mm in diameter at the bottom is 0.54m deep.what will be the total volume of funnel ? plz tell me

Question

anonymous · Answer

still there?

anonymous · Answer

what you are gonna do is

1st - find the average of the two radius

anonymous · Answer

No, don't use the volume of a cone

anonymous · Answer

1st- find the average of the two radii
2nd - plug in the average of the two radii to the usual cylinder formula pi x r^2 x h

zamzam-hussain · Answer

k then

parthkohli · Answer

no

anonymous · Answer

It's a truncated cone

parthkohli · Answer

$$\rm V_{frustum } = \frac{1}{3}\pi h(r_1^2 + r_2 ^2 + r_1 r_2)$$

zamzam-hussain · Answer

oohhh parth kohli thnkx

anonymous · Answer

volume of larger cone - volume of smaller cone :D

mathmate · Answer

I thought @kliedako was going to use the universal formula:
V=h(A1+4A2+A3)/6
which works for cones, prisms, cylinders, pyramids, spheres and even truncated cones.

That would have given:
$\rm V_{truncated~cone}=\dfrac{\pi(r_1^2+4(\frac{r_1+r_2}{2})^2+r_2^2)h}{6}$

which could be simplified to
$\rm V_{truncated~cone} = \frac{1}{3}\pi h(r_1^2 + r_2 ^2 + r_1 r_2)$ as @parthkoli had it.