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Mathematics 17 Online
OpenStudy (anonymous):

Help me with first order ordinary differential equation

OpenStudy (anonymous):

please can any one explain especially the integration part

OpenStudy (ribhu):

yes

OpenStudy (anonymous):

i dont have any question at hand so youll have to explain on your own sorry

OpenStudy (ribhu):

ok lets take an example

OpenStudy (ribhu):

dy/dx = x/y

OpenStudy (ribhu):

rearranging the equation we get ydy = xdx

OpenStudy (ribhu):

integrating both the sides we get: y^2 / 2= x^2 /2 + C

OpenStudy (ribhu):

where C is constant of integration

OpenStudy (anonymous):

ok but can you explain the ones with trigonometric expression or the one in after integration we get ln and especially properties related to ln

OpenStudy (ribhu):

@LilySwan i hope this makes it clear

OpenStudy (anonymous):

OpenStudy (ribhu):

u got a question for this one.

OpenStudy (ribhu):

equation 1 is the solution of differential equation, this solution can be obtained using any specific method, that depends on the question.

OpenStudy (ribhu):

to give a final solution we need to have boundary conditions.

OpenStudy (anonymous):

yep but can you help with finding the value of C1......C3

OpenStudy (ribhu):

yeah i can surely

OpenStudy (ribhu):

there are three BCs Y(2) = 0 , Y' (2)= 2, Y" (2) =6

OpenStudy (ribhu):

now the solution is of the form y= c1x + c2x2 + c3x3

OpenStudy (ribhu):

i am not using the powers but writing it ordinarily.

OpenStudy (ribhu):

we've got Y(2) the value of Y at x=2. get an equation in c1,c2,c3

OpenStudy (ribhu):

differentiating the solution we get 2c2X+3c3x2 = Y'

OpenStudy (ribhu):

similarly Y" = 2c2+6c3x

OpenStudy (ribhu):

@LilySwan u getting

OpenStudy (anonymous):

ya

OpenStudy (ribhu):

so u need to put the particular values of x to get the equations in C1 C2 C3 here in this case 3 constants were there so 3 boundary conditions were required.

OpenStudy (ribhu):

i hope this must have cleared u with something. @LilySwan

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