Help me with first order ordinary differential equation
please can any one explain especially the integration part
yes
i dont have any question at hand so youll have to explain on your own sorry
ok lets take an example
dy/dx = x/y
rearranging the equation we get ydy = xdx
integrating both the sides we get: y^2 / 2= x^2 /2 + C
where C is constant of integration
ok but can you explain the ones with trigonometric expression or the one in after integration we get ln and especially properties related to ln
@LilySwan i hope this makes it clear
Get some popcorn, and try Khan's videos https://www.khanacademy.org/math/differential-equations/first-order-differential-equations/differential-equations-intro/v/differential-equation-introduction
u got a question for this one.
equation 1 is the solution of differential equation, this solution can be obtained using any specific method, that depends on the question.
to give a final solution we need to have boundary conditions.
yep but can you help with finding the value of C1......C3
yeah i can surely
there are three BCs Y(2) = 0 , Y' (2)= 2, Y" (2) =6
now the solution is of the form y= c1x + c2x2 + c3x3
i am not using the powers but writing it ordinarily.
we've got Y(2) the value of Y at x=2. get an equation in c1,c2,c3
differentiating the solution we get 2c2X+3c3x2 = Y'
similarly Y" = 2c2+6c3x
@LilySwan u getting
ya
so u need to put the particular values of x to get the equations in C1 C2 C3 here in this case 3 constants were there so 3 boundary conditions were required.
i hope this must have cleared u with something. @LilySwan
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