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what is the integral of tanx
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i see on a lot of math sites that say its ln secx and others that say -ln cosx
hint: tan(x) = sin(x)/cos(x) use u-substitution and let u = cos(x)
when is it ln secx?
the two are equivalent (just different ways to express the same thing)
so either one i use i will still get the same right answer
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\[\Large -1\ln(\cos(x)) = \ln((\cos(x))^{-1})\] \[\Large -1\ln(\cos(x)) = \ln\left(\frac{1}{\cos(x)^{1}}\right)\] \[\Large -1\ln(\cos(x)) = \ln\left(\frac{1}{\cos(x)}\right)\] \[\Large -1\ln(\cos(x)) = \ln\left(\sec(x)\right)\]
okay thank you for clearing it up
no problem
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