The coffee shop found another delivery company that sells orders at increments of 500 cups, Coffee Delivery B. They charge $3.50 each week to be on their delivery route and charge 3.9 cents per disposable cup.
How do you make a function using the information about the second delivery company? @jim_thompson5910
Is it f(x) = 0.039x + 3.50?
close, you forgot to factor in the fact that they sell "orders at increments of 500 cups"
So how do i do that @jim_thompson5910
You have 2 rates: 500 cups = 1 increment $0.039 = 1 cup And another rate added on: 1 week = $3.50
So, f(x) = 0.039x + 3.50c? I would have to graph this too.
I would do $ per increment plus the weekly rate.
Can you show me how the function will look like?
I'll show you the conversion first.\[\frac{500 cups}{increment}\times\frac{$0.039}{cup}+\frac{$3.50}{week}\\\frac{500\cancel{cups}}{increment}\times\frac{$0.039}{\cancel{cup}}+\frac{$3.50}{week}\\\frac{$19.50}{increment}+\frac{$3.50}{week}\]
Oh I see how you perceive it. Well my function needs to consist of 0.039x or else the teacher might count it as wrong.
If the company has 1 customer that buys 0 cups, they will make $3.50 profit per week. The function is dependent on 2 variables, number of customers and number of increments sold. I would plot it as a function of time, profit over weeks.
ok...so how would i graph it?
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Ok now I understand. Thank you so much!
I am pretty sure your teacher may have something different in mind. Maybe fish for another opinion to consider over mine?
Yeah but I'll try to combine your way and my way, and I'll see how that goes.
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