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OpenStudy (anonymous):
.'.'.' will give medal '.'.'.
find z.
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OpenStudy (adi3):
whts the equation
OpenStudy (anonymous):
|dw:1424606497799:dw|
OpenStudy (anonymous):
im getting z=10.1
OpenStudy (adi3):
how
OpenStudy (adi3):
how did u do it
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OpenStudy (anonymous):
|dw:1424606742761:dw|
OpenStudy (anonymous):
|dw:1424606776704:dw|
OpenStudy (adi3):
okay
OpenStudy (adi3):
how did u get 11.3
OpenStudy (anonymous):
\[y^2=8.2^2+7.8^2\]
\[y=\sqrt{8.2^2+7.8^2}\]
\[y=11.3\]
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OpenStudy (adi3):
okay
OpenStudy (adi3):
how did u get z = 10.1
OpenStudy (anonymous):
\[5^2+z^2=11.3^2\]
\[z^2=11.3^3-5^2\]
\[z=\sqrt{11.3^2-5^2}\]
\[z=10.1\]
OpenStudy (anonymous):
is this right?
OpenStudy (adi3):
did u check your answer
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OpenStudy (anonymous):
yup
OpenStudy (anonymous):
its not from book its from website
OpenStudy (adi3):
is there answer given in the website
OpenStudy (anonymous):
they r saying that my answer is wrong
OpenStudy (anonymous):
no
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OpenStudy (adi3):
lol
OpenStudy (anonymous):
8.2**2+7.8**2-5**2=103**2=10.15 z=10.15
using a bit of a variation of pathagirum theorem
OpenStudy (adi3):
can be
OpenStudy (anonymous):
8.2**2+7.8**2=60.84**2=7.8 y=7.8
OpenStudy (anonymous):
i dont understand
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OpenStudy (anonymous):
Your method is correct and the answer is too. z = 10.15. Since all the values given have two significant digits try entering 10 as the answer.
OpenStudy (anonymous):
oh oookkkkk thanks
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